[xquery-talk] Return nodes and text between nodes

[Gary Larsen]

Hi,



Trying to process both node and text children in a for loop. For some
reason this escapes me.



let $expr :=
<expression><refobj>REFOBJ1</refobj>TEXT1<refobj>REFOBJ2</refobj></expressio
n>

for $x in $expr/* return $x



This returns:



<refobj>REFOBJ1</refobj>
<refobj>REFOBJ2</refobj>



How do I access TEXT1 in a loop?



Thanks,

Gary

[Ronald Bourret]

From the XPath specification:

- child::* selects all element children of the context node

- child::text() selects all text node children of the context node

- child::node() selects all the children of the context node, whatever
their node type

Since "child" is the default axis, you can omit it. Thus, $expr/* will
only return element children, as you have seen. If you want all
children, use $expr/node(). If you only want text children, use
$expr/text().

-- Ron

Hi,
Trying to process both node and text children in a for loop.  For some
reason this escapes me.
let $expr :=
<expression><refobj>REFOBJ1</refobj>TEXT1<refobj>REFOBJ2</refobj></expression>
for $x in $expr/* return $x
<refobj>REFOBJ1</refobj>
<refobj>REFOBJ2</refobj>
How do I access TEXT1 in a loop?
Thanks,
Gary
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